/**In my country, streets dont have names, each of them are * just given a number as name. These numbers are supposed * to be unique but that is not always the case. The local * government allocates some integers to name the roads and * in many case the number of integers allocated is less that * the total number of roads. In that case to make road * names unique some single character suffixes are used. So * roads are named as 1, 2, 3, 1A, 2B, 3C, etc. Of course the * number of suffixes is also always limited to 26 (A, B, . . . , * Z). For example if there are 4 roads and 2 different integers * are allocated for naming then some possible assignments * of names can be: * 1, 2, 1A, 2B * 1, 2, 1A, 2C * 3, 4, 3A, 4A * 1, 2, 1B, 1C * Given the number of roads (R) and the numbers of * integers allocated for naming (N), your job is to determine * minimum how many different suffixes will be required (of * all possible namings) to name the streets assuming that * no two streets can have same names. * Input * The input file can contain up to 10002 lines of inputs. Each line contains two integers R and N * (0 < N, R < 10001). Here R is the total number of streets to be named and N denotes number integers * allocated for naming. * Output * For each line of input produce one line of output. This line contains the serial of output followed by * an integer D which denotes the minimum number of suffixes required to name the streets. If it is not * possible to name all the streets print ‘impossible’ instead (without the quotes). * Sample Input * 8 5 * 100 2 * 0 0 * Sample Output * Case 1: 1 * Case 2: impossible */ //https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2823 import java.util.Scanner; public class NumberingRoads { public static void main(String[] args) { Scanner input = new Scanner(System.in); int caseNumber = 1; while (true) { int first = input.nextInt(); int second = input.nextInt(); if (first == 0 && second == 0) { break; } boolean found = false; for (int i = 0; i < 27 && !found; i++) { int sum = second + second * i; if (sum >= first) { System.out.print("Case " + caseNumber + ": " + i + "\n"); found = true; } } if (!found) { System.out.print("Case " + caseNumber + ": impossible\n"); } caseNumber = caseNumber + 1; } } }